CurriculumGrade 12Mathematics

The Pythagorean Identity

Aligned to F-TF.C.8 — Common Core State Standards for Mathematics.

What this lesson teaches

A point on the unit circle is (cos θ, sin θ) and lies a distance 1 from the origin, so x^2 + y^2 = 1 becomes sin^2(θ) + cos^2(θ) = 1. Given one value and the quadrant, you can find the others.

Worked example

If sin(θ) = 3/5 and θ is in Quadrant I, then cos^2(θ) = 1 − 9/25 = 16/25, so cos(θ) = 4/5 (positive in Quadrant I). Then tan(θ) = sin(θ)/cos(θ) = (3/5)/(4/5) = 3/4.

Practice questions

  1. If cos(θ) = 0.6, find sin^2(θ).
  2. If cos(θ) = −12/13 and θ is in Quadrant II, find sin(θ).
  3. Given sin(θ) = √2/2 in Quadrant I, find cos(θ) and tan(θ).

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Every lesson comes with a video taught in English and Spanish — the same video the QR code in the printed workbook opens.

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En español

La identidad pitagórica

Un punto del círculo unitario es (cos θ, sin θ) y está a distancia 1 del origen, así que x^2 + y^2 = 1 se convierte en sin^2(θ) + cos^2(θ) = 1. Dado un valor y el cuadrante, puedes hallar los demás.

Ejemplo: Si sin(θ) = 3/5 y θ está en el Cuadrante I, entonces cos^2(θ) = 1 − 9/25 = 16/25, así que cos(θ) = 4/5 (positivo en el Cuadrante I). Luego tan(θ) = sin(θ)/cos(θ) = (3/5)/(4/5) = 3/4.

More Functions lessons

Trigonometric Functions and the Unit CircleF-TF.A.2Equivalent Forms of a FunctionF-IF.C.8Comparing Functions in Different FormsF-IF.C.9Building Functions from Two QuantitiesF-BF.A.1Transformations of Function GraphsF-BF.B.3Inverse FunctionsF-BF.B.4

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